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255012401151533 is a prime number
BaseRepresentation
bin111001111110111010110011…
…100101010111111000101101
31020102220221120200212012221002
4321332322303211113320231
5231411110344143322113
62302211025123050045
7104500016012613614
oct7176726345277055
91212827520765832
10255012401151533
1174289174321663
1224727141210925
13ac3a7490633ac
1446d89479b687b
151e736ceed0c58
hexe7eeb3957e2d

255012401151533 has 2 divisors, whose sum is σ = 255012401151534. Its totient is φ = 255012401151532.

The previous prime is 255012401151527. The next prime is 255012401151707. The reversal of 255012401151533 is 335151104210552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 252672229374889 + 2340171776644 = 15895667^2 + 1529762^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255012401151533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255012401151733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127506200575766 + 127506200575767.

It is an arithmetic number, because the mean of its divisors is an integer number (127506200575767).

Almost surely, 2255012401151533 is an apocalyptic number.

It is an amenable number.

255012401151533 is a deficient number, since it is larger than the sum of its proper divisors (1).

255012401151533 is an equidigital number, since it uses as much as digits as its factorization.

255012401151533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90000, while the sum is 38.

The spelling of 255012401151533 in words is "two hundred fifty-five trillion, twelve billion, four hundred one million, one hundred fifty-one thousand, five hundred thirty-three".