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25503005305541 is a prime number
BaseRepresentation
bin1011100110001111000011…
…00100100110101011000101
310100022001201021210200111002
411303013201210212223011
511320320123324234131
6130123530252023045
75241350150234231
oct563074144465305
9110261637720432
1025503005305541
1181428446a6585
122a3a7a0a61a85
13112cc0001716a
146424d00115c1
152e35d1e7b6cb
hex1731e1926ac5

25503005305541 has 2 divisors, whose sum is σ = 25503005305542. Its totient is φ = 25503005305540.

The previous prime is 25503005305423. The next prime is 25503005305549. The reversal of 25503005305541 is 14550350030552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16565022100225 + 8937983205316 = 4070015^2 + 2989646^2 .

It is a cyclic number.

It is not a de Polignac number, because 25503005305541 - 226 = 25502938196677 is a prime.

It is a super-2 number, since 2×255030053055412 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25503005305495 and 25503005305504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25503005305549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12751502652770 + 12751502652771.

It is an arithmetic number, because the mean of its divisors is an integer number (12751502652771).

Almost surely, 225503005305541 is an apocalyptic number.

It is an amenable number.

25503005305541 is a deficient number, since it is larger than the sum of its proper divisors (1).

25503005305541 is an equidigital number, since it uses as much as digits as its factorization.

25503005305541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225000, while the sum is 38.

The spelling of 25503005305541 in words is "twenty-five trillion, five hundred three billion, five million, three hundred five thousand, five hundred forty-one".