Base | Representation |
---|---|
bin | 100101000111001010100… |
… | …000100110101010011010 |
3 | 100000210210201010110102110 |
4 | 211013022200212222122 |
5 | 313241020131314010 |
6 | 5231333033413150 |
7 | 352153065052263 |
oct | 45071240465232 |
9 | 10023721113373 |
10 | 2550313151130 |
11 | 8a3644318418 |
12 | 35232686a1b6 |
13 | 1566552a5894 |
14 | 8b615c3b96a |
15 | 46515c11120 |
hex | 251ca826a9a |
2550313151130 has 64 divisors (see below), whose sum is σ = 6232082208768. Its totient is φ = 667778717760.
The previous prime is 2550313151123. The next prime is 2550313151137. The reversal of 2550313151130 is 311513130552.
It is an interprime number because it is at equal distance from previous prime (2550313151123) and next prime (2550313151137).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is not an unprimeable number, because it can be changed into a prime (2550313151137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1414782 + ... + 2665001.
It is an arithmetic number, because the mean of its divisors is an integer number (97376284512).
Almost surely, 22550313151130 is an apocalyptic number.
2550313151130 is an abundant number, since it is smaller than the sum of its proper divisors (3681769057638).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2550313151130 is a wasteful number, since it uses less digits than its factorization.
2550313151130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4080171.
The product of its (nonzero) digits is 6750, while the sum is 30.
Adding to 2550313151130 its reverse (311513130552), we get a palindrome (2861826281682).
The spelling of 2550313151130 in words is "two trillion, five hundred fifty billion, three hundred thirteen million, one hundred fifty-one thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •