Base | Representation |
---|---|
bin | 111001111111001100011100… |
… | …001010010000111011011011 |
3 | 1020102222202110021012220021202 |
4 | 321333030130022100323123 |
5 | 231411413133343201021 |
6 | 2302223440024224415 |
7 | 104501256145245116 |
oct | 7177143412207333 |
9 | 1212882407186252 |
10 | 255031335522011 |
11 | 74296200281424 |
12 | 2472a94630b10b |
13 | ac3c475a326c9 |
14 | 46d982254957d |
15 | 1e73e3c404a0b |
hex | e7f31c290edb |
255031335522011 has 2 divisors, whose sum is σ = 255031335522012. Its totient is φ = 255031335522010.
The previous prime is 255031335521999. The next prime is 255031335522013. The reversal of 255031335522011 is 110225533130552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255031335522011 - 218 = 255031335259867 is a prime.
Together with 255031335522013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (255031335522013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127515667761005 + 127515667761006.
It is an arithmetic number, because the mean of its divisors is an integer number (127515667761006).
Almost surely, 2255031335522011 is an apocalyptic number.
255031335522011 is a deficient number, since it is larger than the sum of its proper divisors (1).
255031335522011 is an equidigital number, since it uses as much as digits as its factorization.
255031335522011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 135000, while the sum is 38.
Adding to 255031335522011 its reverse (110225533130552), we get a palindrome (365256868652563).
The spelling of 255031335522011 in words is "two hundred fifty-five trillion, thirty-one billion, three hundred thirty-five million, five hundred twenty-two thousand, eleven".
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