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255031335522011 is a prime number
BaseRepresentation
bin111001111111001100011100…
…001010010000111011011011
31020102222202110021012220021202
4321333030130022100323123
5231411413133343201021
62302223440024224415
7104501256145245116
oct7177143412207333
91212882407186252
10255031335522011
1174296200281424
122472a94630b10b
13ac3c475a326c9
1446d982254957d
151e73e3c404a0b
hexe7f31c290edb

255031335522011 has 2 divisors, whose sum is σ = 255031335522012. Its totient is φ = 255031335522010.

The previous prime is 255031335521999. The next prime is 255031335522013. The reversal of 255031335522011 is 110225533130552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255031335522011 - 218 = 255031335259867 is a prime.

Together with 255031335522013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (255031335522013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127515667761005 + 127515667761006.

It is an arithmetic number, because the mean of its divisors is an integer number (127515667761006).

Almost surely, 2255031335522011 is an apocalyptic number.

255031335522011 is a deficient number, since it is larger than the sum of its proper divisors (1).

255031335522011 is an equidigital number, since it uses as much as digits as its factorization.

255031335522011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 255031335522011 its reverse (110225533130552), we get a palindrome (365256868652563).

The spelling of 255031335522011 in words is "two hundred fifty-five trillion, thirty-one billion, three hundred thirty-five million, five hundred twenty-two thousand, eleven".