Base | Representation |
---|---|
bin | 111001111111011000011011… |
… | …000001000101011101010101 |
3 | 1020110000222122220100010000102 |
4 | 321333120123001011131111 |
5 | 231412121011004143110 |
6 | 2302233404421223445 |
7 | 104502223031120153 |
oct | 7177303301053525 |
9 | 1213028586303012 |
10 | 255044201240405 |
11 | 742a0702680045 |
12 | 24731336b61b85 |
13 | ac40746349b25 |
14 | 46da2c311c3d3 |
15 | 1e74441b7e5a5 |
hex | e7f61b045755 |
255044201240405 has 48 divisors (see below), whose sum is σ = 331268048953344. Its totient is φ = 188399414062080.
The previous prime is 255044201240347. The next prime is 255044201240431. The reversal of 255044201240405 is 504042102440552.
It is not a de Polignac number, because 255044201240405 - 222 = 255044197046101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1523268524 + ... + 1523435946.
It is an arithmetic number, because the mean of its divisors is an integer number (6901417686528).
Almost surely, 2255044201240405 is an apocalyptic number.
It is an amenable number.
255044201240405 is a deficient number, since it is larger than the sum of its proper divisors (76223847712939).
255044201240405 is a wasteful number, since it uses less digits than its factorization.
255044201240405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187406 (or 187389 counting only the distinct ones).
The product of its (nonzero) digits is 256000, while the sum is 38.
Adding to 255044201240405 its reverse (504042102440552), we get a palindrome (759086303680957).
The spelling of 255044201240405 in words is "two hundred fifty-five trillion, forty-four billion, two hundred one million, two hundred forty thousand, four hundred five".
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