Base | Representation |
---|---|
bin | 100101000111100101001… |
… | …100110000110000010001 |
3 | 100000211221220201012121122 |
4 | 211013211030300300101 |
5 | 313242424244400132 |
6 | 5231445311132025 |
7 | 352200143130023 |
oct | 45074514606021 |
9 | 10024856635548 |
10 | 2550760934417 |
11 | 8a385405a653 |
12 | 352430814015 |
13 | 1566c6ca75c7 |
14 | 8b6594c0013 |
15 | 465401b2912 |
hex | 251e5330c11 |
2550760934417 has 2 divisors, whose sum is σ = 2550760934418. Its totient is φ = 2550760934416.
The previous prime is 2550760934387. The next prime is 2550760934419. The reversal of 2550760934417 is 7144390670552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2156407077841 + 394353856576 = 1468471^2 + 627976^2 .
It is a cyclic number.
It is not a de Polignac number, because 2550760934417 - 212 = 2550760930321 is a prime.
Together with 2550760934419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2550760934419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275380467208 + 1275380467209.
It is an arithmetic number, because the mean of its divisors is an integer number (1275380467209).
Almost surely, 22550760934417 is an apocalyptic number.
It is an amenable number.
2550760934417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2550760934417 is an equidigital number, since it uses as much as digits as its factorization.
2550760934417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6350400, while the sum is 53.
The spelling of 2550760934417 in words is "two trillion, five hundred fifty billion, seven hundred sixty million, nine hundred thirty-four thousand, four hundred seventeen".
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