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255103125110219 is a prime number
BaseRepresentation
bin111010000000001111010011…
…001001110011110111001011
31020110020121202101222211200002
4322000033103021303313023
5231414102200012011334
62302320431404233215
7104506410152546111
oct7200172311636713
91213217671884602
10255103125110219
117431369a666611
122474084053b80b
13ac46176b62c99
1446dd0b2ac7ab1
151e75c3ebb3b7e
hexe803d3273dcb

255103125110219 has 2 divisors, whose sum is σ = 255103125110220. Its totient is φ = 255103125110218.

The previous prime is 255103125110191. The next prime is 255103125110257. The reversal of 255103125110219 is 912011521301552.

It is an a-pointer prime, because the next prime (255103125110257) can be obtained adding 255103125110219 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255103125110219 is a prime.

It is a super-2 number, since 2×2551031251102192 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (255103125110279) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127551562555109 + 127551562555110.

It is an arithmetic number, because the mean of its divisors is an integer number (127551562555110).

Almost surely, 2255103125110219 is an apocalyptic number.

255103125110219 is a deficient number, since it is larger than the sum of its proper divisors (1).

255103125110219 is an equidigital number, since it uses as much as digits as its factorization.

255103125110219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 38.

The spelling of 255103125110219 in words is "two hundred fifty-five trillion, one hundred three billion, one hundred twenty-five million, one hundred ten thousand, two hundred nineteen".