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2551091854117 is a prime number
BaseRepresentation
bin100101000111111000111…
…011000111101100100101
3100000212210222101200002211
4211013320323013230211
5313244114003312432
65231542212003421
7352211301655342
oct45077073075445
910025728350084
102551091854117
118a3a03932504
12352503600571
1315674a70cb91
148b68b4217c9
154655e27cd47
hex251f8ec7b25

2551091854117 has 2 divisors, whose sum is σ = 2551091854118. Its totient is φ = 2551091854116.

The previous prime is 2551091854097. The next prime is 2551091854123. The reversal of 2551091854117 is 7114581901552.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1414194261601 + 1136897592516 = 1189199^2 + 1066254^2 .

It is a cyclic number.

It is not a de Polignac number, because 2551091854117 - 215 = 2551091821349 is a prime.

It is a super-2 number, since 2×25510918541172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2551091854147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275545927058 + 1275545927059.

It is an arithmetic number, because the mean of its divisors is an integer number (1275545927059).

Almost surely, 22551091854117 is an apocalyptic number.

It is an amenable number.

2551091854117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2551091854117 is an equidigital number, since it uses as much as digits as its factorization.

2551091854117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504000, while the sum is 49.

The spelling of 2551091854117 in words is "two trillion, five hundred fifty-one billion, ninety-one million, eight hundred fifty-four thousand, one hundred seventeen".