Base | Representation |
---|---|
bin | 111010000000010101111111… |
… | …100101110100110010100100 |
3 | 1020110021022022100110200101102 |
4 | 322000111333211310302210 |
5 | 231414211410123240000 |
6 | 2302324020540015232 |
7 | 104510053243511612 |
oct | 7200257745646244 |
9 | 1213238270420342 |
10 | 255110313102500 |
11 | 743167490415a9 |
12 | 24742107831518 |
13 | ac46a510aa85b |
14 | 46dd5955bc6b2 |
15 | 1e76010c643d5 |
hex | e8057f974ca4 |
255110313102500 has 30 divisors (see below), whose sum is σ = 557875232698014. Its totient is φ = 102044125240000.
The previous prime is 255110313102481. The next prime is 255110313102551. The reversal of 255110313102500 is 5201313011552.
255110313102500 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 5 ways, for example, as 106992212439616 + 148118100662884 = 10343704^2 + 12170378^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 51022060121 + ... + 51022065120.
Almost surely, 2255110313102500 is an apocalyptic number.
255110313102500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
255110313102500 is an abundant number, since it is smaller than the sum of its proper divisors (302764919595514).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
255110313102500 is a wasteful number, since it uses less digits than its factorization.
255110313102500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102044125265 (or 102044125248 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 255110313102500 in words is "two hundred fifty-five trillion, one hundred ten billion, three hundred thirteen million, one hundred two thousand, five hundred".
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