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255122140211377 is a prime number
BaseRepresentation
bin111010000000100001000000…
…100010101010100010110001
31020110022102211121021001200221
4322000201000202222202301
5231414410120343231002
62302333254312013041
7104510652315335605
oct7200410042524261
91213272747231627
10255122140211377
117432076814654a
1224744468691181
13ac47bb748a12a
1446ddd98273505
151e764a4232c37
hexe808408aa8b1

255122140211377 has 2 divisors, whose sum is σ = 255122140211378. Its totient is φ = 255122140211376.

The previous prime is 255122140211359. The next prime is 255122140211417. The reversal of 255122140211377 is 773112041221552.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 254969646837361 + 152493374016 = 15967769^2 + 390504^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255122140211377 is a prime.

It is a super-2 number, since 2×2551221402113772 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (255122140211317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105688 + 127561070105689.

It is an arithmetic number, because the mean of its divisors is an integer number (127561070105689).

Almost surely, 2255122140211377 is an apocalyptic number.

It is an amenable number.

255122140211377 is a deficient number, since it is larger than the sum of its proper divisors (1).

255122140211377 is an equidigital number, since it uses as much as digits as its factorization.

255122140211377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 235200, while the sum is 43.

The spelling of 255122140211377 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, three hundred seventy-seven".