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255122140211417 is a prime number
BaseRepresentation
bin111010000000100001000000…
…100010101010100011011001
31020110022102211121021001202102
4322000201000202222203121
5231414410120343231132
62302333254312013145
7104510652315335663
oct7200410042524331
91213272747231672
10255122140211417
1174320768146586
12247444686911b5
13ac47bb748a15b
1446ddd98273533
151e764a4232c62
hexe808408aa8d9

255122140211417 has 2 divisors, whose sum is σ = 255122140211418. Its totient is φ = 255122140211416.

The previous prime is 255122140211377. The next prime is 255122140211431. The reversal of 255122140211417 is 714112041221552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 239214973163776 + 15907167047641 = 15466576^2 + 3988379^2 .

It is a cyclic number.

It is not a de Polignac number, because 255122140211417 - 216 = 255122140145881 is a prime.

It is not a weakly prime, because it can be changed into another prime (255122140211317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105708 + 127561070105709.

It is an arithmetic number, because the mean of its divisors is an integer number (127561070105709).

Almost surely, 2255122140211417 is an apocalyptic number.

It is an amenable number.

255122140211417 is a deficient number, since it is larger than the sum of its proper divisors (1).

255122140211417 is an equidigital number, since it uses as much as digits as its factorization.

255122140211417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44800, while the sum is 38.

Adding to 255122140211417 its reverse (714112041221552), we get a palindrome (969234181432969).

The spelling of 255122140211417 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, four hundred seventeen".