Base | Representation |
---|---|
bin | 111010000000100001000000… |
… | …100010101010100011011111 |
3 | 1020110022102211121021001202122 |
4 | 322000201000202222203133 |
5 | 231414410120343231143 |
6 | 2302333254312013155 |
7 | 104510652315336002 |
oct | 7200410042524337 |
9 | 1213272747231678 |
10 | 255122140211423 |
11 | 74320768146591 |
12 | 247444686911bb |
13 | ac47bb748a164 |
14 | 46ddd98273539 |
15 | 1e764a4232c68 |
hex | e808408aa8df |
255122140211423 has 16 divisors (see below), whose sum is σ = 279326438187264. Its totient is φ = 231966591713280.
The previous prime is 255122140211417. The next prime is 255122140211431. The reversal of 255122140211423 is 324112041221552.
It is a cyclic number.
It is not a de Polignac number, because 255122140211423 - 26 = 255122140211359 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255122140211473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 419195690 + ... + 419803847.
It is an arithmetic number, because the mean of its divisors is an integer number (17457902386704).
Almost surely, 2255122140211423 is an apocalyptic number.
255122140211423 is a deficient number, since it is larger than the sum of its proper divisors (24204297975841).
255122140211423 is a wasteful number, since it uses less digits than its factorization.
255122140211423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 839000162.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 255122140211423 its reverse (324112041221552), we get a palindrome (579234181432975).
The spelling of 255122140211423 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, four hundred twenty-three".
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