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25512214021169 is a prime number
BaseRepresentation
bin1011100110100000001100…
…11101000100010000110001
310100022221111001121220111212
411303100012131010100301
511320443003242134134
6130132052130445505
75242124306102531
oct563200635042061
9110287431556455
1025512214021169
11814673a792967
122a40530a33895
131130a39ab3815
14642b250374c1
152e3970634bce
hex173406744431

25512214021169 has 2 divisors, whose sum is σ = 25512214021170. Its totient is φ = 25512214021168.

The previous prime is 25512214021139. The next prime is 25512214021171. The reversal of 25512214021169 is 96112041221552.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22379172419569 + 3133041601600 = 4730663^2 + 1770040^2 .

It is a cyclic number.

It is not a de Polignac number, because 25512214021169 - 28 = 25512214020913 is a prime.

It is a super-2 number, since 2×255122140211692 (a number of 28 digits) contains 22 as substring.

Together with 25512214021171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (25512214021109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12756107010584 + 12756107010585.

It is an arithmetic number, because the mean of its divisors is an integer number (12756107010585).

Almost surely, 225512214021169 is an apocalyptic number.

It is an amenable number.

25512214021169 is a deficient number, since it is larger than the sum of its proper divisors (1).

25512214021169 is an equidigital number, since it uses as much as digits as its factorization.

25512214021169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 41.

The spelling of 25512214021169 in words is "twenty-five trillion, five hundred twelve billion, two hundred fourteen million, twenty-one thousand, one hundred sixty-nine".