Base | Representation |
---|---|
bin | 1001100000010011… |
… | …1100011110101010 |
3 | 20120210222020021100 |
4 | 2120010330132222 |
5 | 20211131330010 |
6 | 1101102022230 |
7 | 120140552361 |
oct | 23004743652 |
9 | 6523866240 |
10 | 2551433130 |
11 | 109a243524 |
12 | 5b2577976 |
13 | 318799c5c |
14 | 1a2bdc7d8 |
15 | ededa2c0 |
hex | 9813c7aa |
2551433130 has 24 divisors (see below), whose sum is σ = 6633726372. Its totient is φ = 680382144.
The previous prime is 2551433123. The next prime is 2551433149. The reversal of 2551433130 is 313341552.
It can be written as a sum of positive squares in 2 ways, for example, as 2375685081 + 175748049 = 48741^2 + 13257^2 .
It is a super-2 number, since 2×25514331302 = 13019622033723193800, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2551433094 and 2551433103.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14174539 + ... + 14174718.
Almost surely, 22551433130 is an apocalyptic number.
2551433130 is an abundant number, since it is smaller than the sum of its proper divisors (4082293242).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2551433130 is a wasteful number, since it uses less digits than its factorization.
2551433130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28349270 (or 28349267 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
The square root of 2551433130 is about 50511.7128001021. The cubic root of 2551433130 is about 1366.4530997498.
Adding to 2551433130 its reverse (313341552), we get a palindrome (2864774682).
The spelling of 2551433130 in words is "two billion, five hundred fifty-one million, four hundred thirty-three thousand, one hundred thirty".
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