Search a number
-
+
2551557905837 is a prime number
BaseRepresentation
bin100101001000010100101…
…100111101110110101101
3100000221000110100112212122
4211020110230331312231
5313301042310441322
65232100341042325
7352225661230613
oct45102454756655
910027013315778
102551557905837
118a4122a12016
123526136b63a5
131567c3139b25
148b6d329b6b3
154658a13c442
hex25214b3ddad

2551557905837 has 2 divisors, whose sum is σ = 2551557905838. Its totient is φ = 2551557905836.

The previous prime is 2551557905737. The next prime is 2551557905839. The reversal of 2551557905837 is 7385097551552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2080592765476 + 470965140361 = 1442426^2 + 686269^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2551557905837 is a prime.

Together with 2551557905839, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2551557905837.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2551557905839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275778952918 + 1275778952919.

It is an arithmetic number, because the mean of its divisors is an integer number (1275778952919).

Almost surely, 22551557905837 is an apocalyptic number.

It is an amenable number.

2551557905837 is a deficient number, since it is larger than the sum of its proper divisors (1).

2551557905837 is an equidigital number, since it uses as much as digits as its factorization.

2551557905837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 66150000, while the sum is 62.

The spelling of 2551557905837 in words is "two trillion, five hundred fifty-one billion, five hundred fifty-seven million, nine hundred five thousand, eight hundred thirty-seven".