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2553009140501 is a prime number
BaseRepresentation
bin100101001001101011001…
…100111111001100010101
3100001001202121002220120122
4211021223030333030111
5313312030314444001
65232500342041325
7352306642432511
oct45115314771425
910031677086518
102553009140501
118a47a8115106
12352959719245
131569949b6971
148b7cdd09141
1546622752b1b
hex2526b33f315

2553009140501 has 2 divisors, whose sum is σ = 2553009140502. Its totient is φ = 2553009140500.

The previous prime is 2553009140449. The next prime is 2553009140503. The reversal of 2553009140501 is 1050419003552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2535104024401 + 17905116100 = 1592201^2 + 133810^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553009140501 - 226 = 2552942031637 is a prime.

Together with 2553009140503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2553009140503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276504570250 + 1276504570251.

It is an arithmetic number, because the mean of its divisors is an integer number (1276504570251).

Almost surely, 22553009140501 is an apocalyptic number.

It is an amenable number.

2553009140501 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553009140501 is an equidigital number, since it uses as much as digits as its factorization.

2553009140501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 35.

The spelling of 2553009140501 in words is "two trillion, five hundred fifty-three billion, nine million, one hundred forty thousand, five hundred one".