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255513239 is a prime number
BaseRepresentation
bin11110011101011…
…01001010010111
3122210210102021022
433032231022113
51010402410424
641204311355
76221553362
oct1716551227
9583712238
10255513239
11121259973
12716a255b
1340c22c87
1425d130d9
151767295e
hexf3ad297

255513239 has 2 divisors, whose sum is σ = 255513240. Its totient is φ = 255513238.

The previous prime is 255513221. The next prime is 255513241. The reversal of 255513239 is 932315552.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255513239 is a prime.

It is a super-2 number, since 2×2555132392 = 130574030608542242, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 255513241, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p13964309 and since 255513239 and 13964309 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 255513199 and 255513208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255513289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127756619 + 127756620.

It is an arithmetic number, because the mean of its divisors is an integer number (127756620).

Almost surely, 2255513239 is an apocalyptic number.

255513239 is a deficient number, since it is larger than the sum of its proper divisors (1).

255513239 is an equidigital number, since it uses as much as digits as its factorization.

255513239 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 40500, while the sum is 35.

The square root of 255513239 is about 15984.7814811464. The cubic root of 255513239 is about 634.5577253853.

The spelling of 255513239 in words is "two hundred fifty-five million, five hundred thirteen thousand, two hundred thirty-nine".