Base | Representation |
---|---|
bin | 1110111000001110101… |
… | …1010001110010000111 |
3 | 220102210001111201102221 |
4 | 3232003223101302013 |
5 | 13141443212341131 |
6 | 313232053113211 |
7 | 24316211053441 |
oct | 3560353216207 |
9 | 812701451387 |
10 | 255612230791 |
11 | 9944a493315 |
12 | 41658028807 |
13 | 1b147a09408 |
14 | c52bd21491 |
15 | 69b08a7411 |
hex | 3b83ad1c87 |
255612230791 has 2 divisors, whose sum is σ = 255612230792. Its totient is φ = 255612230790.
The previous prime is 255612230777. The next prime is 255612230813. The reversal of 255612230791 is 197032216552.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255612230791 - 219 = 255611706503 is a prime.
It is a super-4 number, since 4×2556122307914 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255612230891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127806115395 + 127806115396.
It is an arithmetic number, because the mean of its divisors is an integer number (127806115396).
Almost surely, 2255612230791 is an apocalyptic number.
255612230791 is a deficient number, since it is larger than the sum of its proper divisors (1).
255612230791 is an equidigital number, since it uses as much as digits as its factorization.
255612230791 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 255612230791 in words is "two hundred fifty-five billion, six hundred twelve million, two hundred thirty thousand, seven hundred ninety-one".
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