Base | Representation |
---|---|
bin | 100101001100110011100… |
… | …001010101010011110101 |
3 | 100001101102211000001110201 |
4 | 211030303201111103311 |
5 | 313340421144322143 |
6 | 5234214035120501 |
7 | 352456141525312 |
oct | 45146341252365 |
9 | 10041384001421 |
10 | 2556369917173 |
11 | 8a61721a0396 |
12 | 353537143131 |
13 | 1570ac058607 |
14 | 8ba2c3c5d09 |
15 | 4676c80d64d |
hex | 253338554f5 |
2556369917173 has 2 divisors, whose sum is σ = 2556369917174. Its totient is φ = 2556369917172.
The previous prime is 2556369917083. The next prime is 2556369917201. The reversal of 2556369917173 is 3717199636552.
2556369917173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1562157518769 + 994212398404 = 1249863^2 + 997102^2 .
It is a cyclic number.
It is not a de Polignac number, because 2556369917173 - 221 = 2556367820021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2556369917273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278184958586 + 1278184958587.
It is an arithmetic number, because the mean of its divisors is an integer number (1278184958587).
Almost surely, 22556369917173 is an apocalyptic number.
It is an amenable number.
2556369917173 is a deficient number, since it is larger than the sum of its proper divisors (1).
2556369917173 is an equidigital number, since it uses as much as digits as its factorization.
2556369917173 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64297800, while the sum is 64.
The spelling of 2556369917173 in words is "two trillion, five hundred fifty-six billion, three hundred sixty-nine million, nine hundred seventeen thousand, one hundred seventy-three".
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