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2557314631 is a prime number
BaseRepresentation
bin1001100001101101…
…1000011001000111
320121020001001011201
42120123120121013
520214133032011
61101432043331
7120241546534
oct23033303107
96536031151
102557314631
1110a25a0373
125b4533547
13319a79031
141a38cdd8b
15ee79ccc1
hex986d8647

2557314631 has 2 divisors, whose sum is σ = 2557314632. Its totient is φ = 2557314630.

The previous prime is 2557314629. The next prime is 2557314637. The reversal of 2557314631 is 1364137552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2557314631 - 21 = 2557314629 is a prime.

It is a super-2 number, since 2×25573146312 = 13079716243853332322, which contains 22 as substring.

Together with 2557314629, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2557314637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278657315 + 1278657316.

It is an arithmetic number, because the mean of its divisors is an integer number (1278657316).

Almost surely, 22557314631 is an apocalyptic number.

2557314631 is a deficient number, since it is larger than the sum of its proper divisors (1).

2557314631 is an equidigital number, since it uses as much as digits as its factorization.

2557314631 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 75600, while the sum is 37.

The square root of 2557314631 is about 50569.8984673689. The cubic root of 2557314631 is about 1367.5022653693.

It can be divided in two parts, 25573 and 14631, that added together give a palindrome (40204).

The spelling of 2557314631 in words is "two billion, five hundred fifty-seven million, three hundred fourteen thousand, six hundred thirty-one".