Base | Representation |
---|---|
bin | 111010001110101111110110… |
… | …001011010100111111111000 |
3 | 1020120202221020110001020121222 |
4 | 322032233312023110333320 |
5 | 232031421044122421240 |
6 | 2304402441003251212 |
7 | 104641424224044521 |
oct | 7216576613247770 |
9 | 1216687213036558 |
10 | 256100145123320 |
11 | 74668509450213 |
12 | 24881b10519b08 |
13 | acb91a8933664 |
14 | 4735455457848 |
15 | 1e91b449daeb5 |
hex | e8ebf62d4ff8 |
256100145123320 has 64 divisors (see below), whose sum is σ = 578751395220000. Its totient is φ = 101990994329088.
The previous prime is 256100145123299. The next prime is 256100145123401. The reversal of 256100145123320 is 23321541001652.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 633202679 + ... + 633607001.
Almost surely, 2256100145123320 is an apocalyptic number.
256100145123320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
256100145123320 is an abundant number, since it is smaller than the sum of its proper divisors (322651250096680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
256100145123320 is a wasteful number, since it uses less digits than its factorization.
256100145123320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 473712 (or 473708 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 256100145123320 its reverse (23321541001652), we get a palindrome (279421686124972).
The spelling of 256100145123320 in words is "two hundred fifty-six trillion, one hundred billion, one hundred forty-five million, one hundred twenty-three thousand, three hundred twenty".
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