256101045413 has 2 divisors, whose sum is σ = 256101045414. Its totient is φ = 256101045412.

The previous prime is 256101045379. The next prime is 256101045437. The reversal of 256101045413 is 314540101652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 190827438244 + 65273607169 = 436838^2 + 255487^2 .

It is a cyclic number.

It is not a de Polignac number, because 256101045413 - 2¹⁴ = 256101029029 is a prime.

It is a super-3 number, since 3×256101045413³ (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 256101045413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (256101045313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128050522706 + 128050522707.

It is an arithmetic number, because the mean of its divisors is an integer number (128050522707).

Almost surely, 2^256101045413 is an apocalyptic number.

It is an amenable number.

256101045413 is a deficient number, since it is larger than the sum of its proper divisors (1).

256101045413 is an equidigital number, since it uses as much as digits as its factorization.

256101045413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 256101045413 in words is "two hundred fifty-six billion, one hundred one million, forty-five thousand, four hundred thirteen".