2561011200 has 720 divisors, whose sum is σ = 10448545536. Its totient is φ = 593510400.

The previous prime is 2561011183. The next prime is 2561011259. The reversal of 2561011200 is 21101652.

2561011200 is a `hidden beast` number, since 25 + 610 + 11 + 20 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 54489577 + ... + 54489623.

Almost surely, 2^2561011200 is an apocalyptic number.

2561011200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2561011200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5224272768).

2561011200 is an abundant number, since it is smaller than the sum of its proper divisors (7887534336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2561011200 is a wasteful number, since it uses less digits than its factorization.

2561011200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135 (or 111 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

The square root of 2561011200 is about 50606.4343735063. The cubic root of 2561011200 is about 1368.1608510975.

Adding to 2561011200 its reverse (21101652), we get a palindrome (2582112852).

The spelling of 2561011200 in words is "two billion, five hundred sixty-one million, eleven thousand, two hundred".