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2561144317 is a prime number
BaseRepresentation
bin1001100010100111…
…1111010111111101
320121111020121111221
42120221333113331
520221123104232
61102050113341
7120316240024
oct23051772775
96544217457
102561144317
1110a47766a6
125b587b851
1331a7ba214
141a42098bb
15eeca7897
hex98a7f5fd

2561144317 has 2 divisors, whose sum is σ = 2561144318. Its totient is φ = 2561144316.

The previous prime is 2561144293. The next prime is 2561144347. The reversal of 2561144317 is 7134411652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2091598756 + 469545561 = 45734^2 + 21669^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2561144317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2561144347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280572158 + 1280572159.

It is an arithmetic number, because the mean of its divisors is an integer number (1280572159).

Almost surely, 22561144317 is an apocalyptic number.

It is an amenable number.

2561144317 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561144317 is an equidigital number, since it uses as much as digits as its factorization.

2561144317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 34.

The square root of 2561144317 is about 50607.7495745464. The cubic root of 2561144317 is about 1368.1845555770.

Adding to 2561144317 its reverse (7134411652), we get a palindrome (9695555969).

The spelling of 2561144317 in words is "two billion, five hundred sixty-one million, one hundred forty-four thousand, three hundred seventeen".