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2561401233767 = 24154071965641
BaseRepresentation
bin100101010001011111011…
…010010010000101100111
3100001212102110022102022202
4211101133122102011213
5313431222203440032
65240405205445115
7353024624153645
oct45213732220547
910055373272282
102561401233767
118a8314247a82
1235450011079b
1315770153051c
148bd886ba195
154696439dd62
hex2545f692167

2561401233767 has 8 divisors (see below), whose sum is σ = 2572506448512. Its totient is φ = 2550299961600.

The previous prime is 2561401233751. The next prime is 2561401233793. The reversal of 2561401233767 is 7673321041652.

It is a happy number.

2561401233767 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2561401233767 - 24 = 2561401233751 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2561401233367) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 320267 + ... + 2285907.

It is an arithmetic number, because the mean of its divisors is an integer number (321563306064).

Almost surely, 22561401233767 is an apocalyptic number.

2561401233767 is a deficient number, since it is larger than the sum of its proper divisors (11105214745).

2561401233767 is a wasteful number, since it uses less digits than its factorization.

2561401233767 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1971289.

The product of its (nonzero) digits is 1270080, while the sum is 47.

The spelling of 2561401233767 in words is "two trillion, five hundred sixty-one billion, four hundred one million, two hundred thirty-three thousand, seven hundred sixty-seven".

Divisors: 1 241 5407 1303087 1965641 473719481 10628220887 2561401233767