Base | Representation |
---|---|
bin | 110001000010… |
… | …1001100111101 |
3 | 1210101021102212 |
4 | 1202011030331 |
5 | 23040231141 |
6 | 2315030205 |
7 | 431354261 |
oct | 142051475 |
9 | 53337385 |
10 | 25711421 |
11 | 1357140a |
12 | 873b365 |
13 | 5432c78 |
14 | 35b40a1 |
15 | 23cd2eb |
hex | 188533d |
25711421 has 2 divisors, whose sum is σ = 25711422. Its totient is φ = 25711420.
The previous prime is 25711391. The next prime is 25711423. The reversal of 25711421 is 12411752.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22905796 + 2805625 = 4786^2 + 1675^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25711421 is a prime.
It is a super-2 number, since 2×257114212 = 1322154339678482, which contains 22 as substring.
It is a Sophie Germain prime.
Together with 25711423, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25711423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12855710 + 12855711.
It is an arithmetic number, because the mean of its divisors is an integer number (12855711).
Almost surely, 225711421 is an apocalyptic number.
It is an amenable number.
25711421 is a deficient number, since it is larger than the sum of its proper divisors (1).
25711421 is an equidigital number, since it uses as much as digits as its factorization.
25711421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 560, while the sum is 23.
The square root of 25711421 is about 5070.6430558658. The cubic root of 25711421 is about 295.1494827971.
The spelling of 25711421 in words is "twenty-five million, seven hundred eleven thousand, four hundred twenty-one".
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