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257150057 is a prime number
BaseRepresentation
bin11110101001111…
…00110001101001
3122220212120120012
433110330301221
51011312300212
641303341305
76241511423
oct1724746151
9586776505
10257150057
1112217770a
1272151835
1341376cc8
142621b813
1517897922
hexf53cc69

257150057 has 2 divisors, whose sum is σ = 257150058. Its totient is φ = 257150056.

The previous prime is 257150021. The next prime is 257150059. The reversal of 257150057 is 750051752.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 256608361 + 541696 = 16019^2 + 736^2 .

It is a cyclic number.

It is not a de Polignac number, because 257150057 - 28 = 257149801 is a prime.

It is a super-3 number, since 3×2571500573 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 257150059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (257150059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128575028 + 128575029.

It is an arithmetic number, because the mean of its divisors is an integer number (128575029).

Almost surely, 2257150057 is an apocalyptic number.

It is an amenable number.

257150057 is a deficient number, since it is larger than the sum of its proper divisors (1).

257150057 is an equidigital number, since it uses as much as digits as its factorization.

257150057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12250, while the sum is 32.

The square root of 257150057 is about 16035.8990081629. The cubic root of 257150057 is about 635.9098346989.

The spelling of 257150057 in words is "two hundred fifty-seven million, one hundred fifty thousand, fifty-seven".