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25724543131361 is a prime number
BaseRepresentation
bin1011101100101011101100…
…10000010101111011100001
310101002020112122022021200002
411312111312100111323201
511332432331020200421
6130413405244305345
75263352105544314
oct566256620257341
9111066478267602
1025724543131361
118218798a62028
122a75709542255
131147a774b8269
1464d10872697b
152e924b188b0b
hex176576415ee1

25724543131361 has 2 divisors, whose sum is σ = 25724543131362. Its totient is φ = 25724543131360.

The previous prime is 25724543131283. The next prime is 25724543131363. The reversal of 25724543131361 is 16313134542752.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21648408256225 + 4076134875136 = 4652785^2 + 2018944^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25724543131361 is a prime.

Together with 25724543131363, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (25724543131363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12862271565680 + 12862271565681.

It is an arithmetic number, because the mean of its divisors is an integer number (12862271565681).

Almost surely, 225724543131361 is an apocalyptic number.

It is an amenable number.

25724543131361 is a deficient number, since it is larger than the sum of its proper divisors (1).

25724543131361 is an equidigital number, since it uses as much as digits as its factorization.

25724543131361 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1814400, while the sum is 47.

The spelling of 25724543131361 in words is "twenty-five trillion, seven hundred twenty-four billion, five hundred forty-three million, one hundred thirty-one thousand, three hundred sixty-one".