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258325117 is a prime number
BaseRepresentation
bin11110110010110…
…11101001111101
3200000002021102221
433121123221331
51012112400432
641344445341
76254504311
oct1731335175
9600067387
10258325117
111228aa536
1272619851
1341698acb
1426445b41
1517a2ab97
hexf65ba7d

258325117 has 2 divisors, whose sum is σ = 258325118. Its totient is φ = 258325116.

The previous prime is 258325099. The next prime is 258325129. The reversal of 258325117 is 711523852.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 202464441 + 55860676 = 14229^2 + 7474^2 .

It is a cyclic number.

It is not a de Polignac number, because 258325117 - 223 = 249936509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (258325147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129162558 + 129162559.

It is an arithmetic number, because the mean of its divisors is an integer number (129162559).

Almost surely, 2258325117 is an apocalyptic number.

It is an amenable number.

258325117 is a deficient number, since it is larger than the sum of its proper divisors (1).

258325117 is an equidigital number, since it uses as much as digits as its factorization.

258325117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16800, while the sum is 34.

The square root of 258325117 is about 16072.4956680660. The cubic root of 258325117 is about 636.8769702929.

Adding to 258325117 its reverse (711523852), we get a palindrome (969848969).

The spelling of 258325117 in words is "two hundred fifty-eight million, three hundred twenty-five thousand, one hundred seventeen".