258404503853 has 2 divisors, whose sum is σ = 258404503854. Its totient is φ = 258404503852.

The previous prime is 258404503837. The next prime is 258404503909. The reversal of 258404503853 is 358305404852.

258404503853 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 160586937289 + 97817566564 = 400733^2 + 312758^2 .

It is a cyclic number.

It is not a de Polignac number, because 258404503853 - 2⁴ = 258404503837 is a prime.

It is a super-2 number, since 2×258404503853² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 258404503798 and 258404503807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (258404503153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129202251926 + 129202251927.

It is an arithmetic number, because the mean of its divisors is an integer number (129202251927).

Almost surely, 2^258404503853 is an apocalyptic number.

It is an amenable number.

258404503853 is a deficient number, since it is larger than the sum of its proper divisors (1).

258404503853 is an equidigital number, since it uses as much as digits as its factorization.

258404503853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304000, while the sum is 47.

Subtracting 258404503853 from its reverse (358305404852), we obtain a palindrome (99900900999).

The spelling of 258404503853 in words is "two hundred fifty-eight billion, four hundred four million, five hundred three thousand, eight hundred fifty-three".