2599140539 has 2 divisors, whose sum is σ = 2599140540. Its totient is φ = 2599140538.

The previous prime is 2599140503. The next prime is 2599140541. The reversal of 2599140539 is 9350419952.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2599140539 is a prime.

Together with 2599140541, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2599140493 and 2599140502.

It is not a weakly prime, because it can be changed into another prime (2599140569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1299570269 + 1299570270.

It is an arithmetic number, because the mean of its divisors is an integer number (1299570270).

Almost surely, 2^2599140539 is an apocalyptic number.

2599140539 is a deficient number, since it is larger than the sum of its proper divisors (1).

2599140539 is an equidigital number, since it uses as much as digits as its factorization.

2599140539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 437400, while the sum is 47.

The square root of 2599140539 is about 50981.7667308617. The cubic root of 2599140539 is about 1374.9173352397.

The spelling of 2599140539 in words is "two billion, five hundred ninety-nine million, one hundred forty thousand, five hundred thirty-nine".