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2604113557 is a prime number
BaseRepresentation
bin1001101100110111…
…1001111010010101
320201111002200020021
42123031321322111
520313123113212
61110223105141
7121350412543
oct23315717225
96644080207
102604113557
111116a55071
126081421b1
133266833c6
141a9bd2d93
15103944307
hex9b379e95

2604113557 has 2 divisors, whose sum is σ = 2604113558. Its totient is φ = 2604113556.

The previous prime is 2604113543. The next prime is 2604113563. The reversal of 2604113557 is 7553114062.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1569268996 + 1034844561 = 39614^2 + 32169^2 .

It is a cyclic number.

It is not a de Polignac number, because 2604113557 - 211 = 2604111509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2604113587) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1302056778 + 1302056779.

It is an arithmetic number, because the mean of its divisors is an integer number (1302056779).

Almost surely, 22604113557 is an apocalyptic number.

It is an amenable number.

2604113557 is a deficient number, since it is larger than the sum of its proper divisors (1).

2604113557 is an equidigital number, since it uses as much as digits as its factorization.

2604113557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

The square root of 2604113557 is about 51030.5159389948. The cubic root of 2604113557 is about 1375.7936675489.

The spelling of 2604113557 in words is "two billion, six hundred four million, one hundred thirteen thousand, five hundred fifty-seven".