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2604650117 is a prime number
BaseRepresentation
bin1001101100111111…
…1100111010000101
320201112002221020212
42123033330322011
520313242300432
61110242405205
7121355106056
oct23317747205
96645087225
102604650117
111117291203
12608360805
133268106b4
141a9cd272d
151039ed2b2
hex9b3fce85

2604650117 has 2 divisors, whose sum is σ = 2604650118. Its totient is φ = 2604650116.

The previous prime is 2604650107. The next prime is 2604650129. The reversal of 2604650117 is 7110564062.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1597920676 + 1006729441 = 39974^2 + 31729^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2604650117 is a prime.

It is a super-2 number, since 2×26046501172 = 13568404463976227378, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2604650107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1302325058 + 1302325059.

It is an arithmetic number, because the mean of its divisors is an integer number (1302325059).

Almost surely, 22604650117 is an apocalyptic number.

It is an amenable number.

2604650117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2604650117 is an equidigital number, since it uses as much as digits as its factorization.

2604650117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

The square root of 2604650117 is about 51035.7729146919. The cubic root of 2604650117 is about 1375.8881520558. Note that the first 3 decimals are identical.

The spelling of 2604650117 in words is "two billion, six hundred four million, six hundred fifty thousand, one hundred seventeen".