Base | Representation |
---|---|
bin | 100101111101110001111… |
… | …011001010111000110101 |
3 | 100020102011122220111100101 |
4 | 211331301323022320311 |
5 | 320221120330011143 |
6 | 5314312115514101 |
7 | 356330242136533 |
oct | 45756173127065 |
9 | 10212148814311 |
10 | 2608956485173 |
11 | 9164a7a14245 |
12 | 3617722b8931 |
13 | 15c03c94753c |
14 | 903ba45d153 |
15 | 47ce92cdb4d |
hex | 25f71ecae35 |
2608956485173 has 2 divisors, whose sum is σ = 2608956485174. Its totient is φ = 2608956485172.
The previous prime is 2608956485167. The next prime is 2608956485183. The reversal of 2608956485173 is 3715846598062.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1443405210724 + 1165551274449 = 1201418^2 + 1079607^2 .
It is a cyclic number.
It is not a de Polignac number, because 2608956485173 - 217 = 2608956354101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2608956485183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1304478242586 + 1304478242587.
It is an arithmetic number, because the mean of its divisors is an integer number (1304478242587).
It is a 1-persistent number, because it is pandigital, but 2⋅2608956485173 = 5217912970346 is not.
Almost surely, 22608956485173 is an apocalyptic number.
It is an amenable number.
2608956485173 is a deficient number, since it is larger than the sum of its proper divisors (1).
2608956485173 is an equidigital number, since it uses as much as digits as its factorization.
2608956485173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 87091200, while the sum is 64.
The spelling of 2608956485173 in words is "two trillion, six hundred eight billion, nine hundred fifty-six million, four hundred eighty-five thousand, one hundred seventy-three".
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