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261270273116441 is a prime number
BaseRepresentation
bin111011011001111110111001…
…110100011100100100011001
31021021002012020112222212201102
4323121332321310130210121
5233221123004404211231
62323401523445201145
7106014103633636631
oct7331767164344431
91237065215885642
10261270273116441
1176281111965a86
1225377b19a001b5
13b2a28b1316b74
1448737978736c1
15203138cddbacb
hexed9fb9d1c919

261270273116441 has 2 divisors, whose sum is σ = 261270273116442. Its totient is φ = 261270273116440.

The previous prime is 261270273116431. The next prime is 261270273116443. The reversal of 261270273116441 is 144611372072162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 261269885184025 + 387932416 = 16163845^2 + 19696^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-261270273116441 is a prime.

It is a super-2 number, since 2×2612702731164412 (a number of 30 digits) contains 22 as substring.

Together with 261270273116443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (261270273116443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130635136558220 + 130635136558221.

It is an arithmetic number, because the mean of its divisors is an integer number (130635136558221).

Almost surely, 2261270273116441 is an apocalyptic number.

It is an amenable number.

261270273116441 is a deficient number, since it is larger than the sum of its proper divisors (1).

261270273116441 is an equidigital number, since it uses as much as digits as its factorization.

261270273116441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 677376, while the sum is 47.

The spelling of 261270273116441 in words is "two hundred sixty-one trillion, two hundred seventy billion, two hundred seventy-three million, one hundred sixteen thousand, four hundred forty-one".