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261334101433157 is a prime number
BaseRepresentation
bin111011011010111010010110…
…010010001001101101000101
31021021022021222212020022201122
4323122322112102021231011
5233223144214431330112
62323451121231403325
7106021523440451564
oct7332722622115505
91237267885208648
10261334101433157
11762a6196325055
1225388371983545
13b2a8913c441cc
1448768d0949bdb
152032d767a0872
hexedae96489b45

261334101433157 has 2 divisors, whose sum is σ = 261334101433158. Its totient is φ = 261334101433156.

The previous prime is 261334101433151. The next prime is 261334101433169. The reversal of 261334101433157 is 751334101433162.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 166020158384161 + 95313943048996 = 12884881^2 + 9762886^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-261334101433157 is a prime.

It is a super-2 number, since 2×2613341014331572 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (261334101433151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130667050716578 + 130667050716579.

It is an arithmetic number, because the mean of its divisors is an integer number (130667050716579).

Almost surely, 2261334101433157 is an apocalyptic number.

It is an amenable number.

261334101433157 is a deficient number, since it is larger than the sum of its proper divisors (1).

261334101433157 is an equidigital number, since it uses as much as digits as its factorization.

261334101433157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 44.

The spelling of 261334101433157 in words is "two hundred sixty-one trillion, three hundred thirty-four billion, one hundred one million, four hundred thirty-three thousand, one hundred fifty-seven".