Search a number
-
+
261334101433169 is a prime number
BaseRepresentation
bin111011011010111010010110…
…010010001001101101010001
31021021022021222212020022202002
4323122322112102021231101
5233223144214431330134
62323451121231403345
7106021523440451612
oct7332722622115521
91237267885208662
10261334101433169
11762a6196325066
1225388371983555
13b2a8913c4420b
1448768d0949c09
152032d767a087e
hexedae96489b51

261334101433169 has 2 divisors, whose sum is σ = 261334101433170. Its totient is φ = 261334101433168.

The previous prime is 261334101433157. The next prime is 261334101433187. The reversal of 261334101433169 is 961334101433162.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 256796298268225 + 4537803164944 = 16024865^2 + 2130212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-261334101433169 is a prime.

It is a super-2 number, since 2×2613341014331692 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (261334101433109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130667050716584 + 130667050716585.

It is an arithmetic number, because the mean of its divisors is an integer number (130667050716585).

Almost surely, 2261334101433169 is an apocalyptic number.

It is an amenable number.

261334101433169 is a deficient number, since it is larger than the sum of its proper divisors (1).

261334101433169 is an equidigital number, since it uses as much as digits as its factorization.

261334101433169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 47.

The spelling of 261334101433169 in words is "two hundred sixty-one trillion, three hundred thirty-four billion, one hundred one million, four hundred thirty-three thousand, one hundred sixty-nine".