Base | Representation |
---|---|
bin | 1111001101100101001… |
… | …1110110111000000111 |
3 | 220222120111122122021222 |
4 | 3303121103312320013 |
5 | 13240213014233033 |
6 | 320020522430555 |
7 | 24611226330005 |
oct | 3633123667007 |
9 | 828514578258 |
10 | 261343899143 |
11 | a09208aa608 |
12 | 4279766245b |
13 | 1b84c314852 |
14 | c913241a75 |
15 | 6be8b89598 |
hex | 3cd94f6e07 |
261343899143 has 2 divisors, whose sum is σ = 261343899144. Its totient is φ = 261343899142.
The previous prime is 261343899119. The next prime is 261343899151. The reversal of 261343899143 is 341998343162.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 261343899143 - 210 = 261343898119 is a prime.
It is a super-2 number, since 2×2613438991432 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (261343899043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130671949571 + 130671949572.
It is an arithmetic number, because the mean of its divisors is an integer number (130671949572).
Almost surely, 2261343899143 is an apocalyptic number.
261343899143 is a deficient number, since it is larger than the sum of its proper divisors (1).
261343899143 is an equidigital number, since it uses as much as digits as its factorization.
261343899143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3359232, while the sum is 53.
The spelling of 261343899143 in words is "two hundred sixty-one billion, three hundred forty-three million, eight hundred ninety-nine thousand, one hundred forty-three".
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