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263318049149 is a prime number
BaseRepresentation
bin1111010100111011111…
…0101001000101111101
3221011200002100211222212
43311032332221011331
513303233410033044
6320544443350205
725011160326251
oct3651676510575
9834602324885
10263318049149
11a17441a0741
1243048822365
131baa530ab4c
14ca5d4cc261
156cb2142a9e
hex3d4efa917d

263318049149 has 2 divisors, whose sum is σ = 263318049150. Its totient is φ = 263318049148.

The previous prime is 263318049103. The next prime is 263318049151. The reversal of 263318049149 is 941940813362.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143882145124 + 119435904025 = 379318^2 + 345595^2 .

It is a cyclic number.

It is not a de Polignac number, because 263318049149 - 232 = 259023081853 is a prime.

Together with 263318049151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 263318049097 and 263318049106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (263318045149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 131659024574 + 131659024575.

It is an arithmetic number, because the mean of its divisors is an integer number (131659024575).

Almost surely, 2263318049149 is an apocalyptic number.

It is an amenable number.

263318049149 is a deficient number, since it is larger than the sum of its proper divisors (1).

263318049149 is an equidigital number, since it uses as much as digits as its factorization.

263318049149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1119744, while the sum is 50.

The spelling of 263318049149 in words is "two hundred sixty-three billion, three hundred eighteen million, forty-nine thousand, one hundred forty-nine".