Base | Representation |
---|---|
bin | 1100000000010001010111… |
… | …01011010111001110100111 |
3 | 10110110120211020220200022012 |
4 | 12000020223223113032213 |
5 | 11424444242024220324 |
6 | 132050520231224435 |
7 | 5363110116000611 |
oct | 600105353271647 |
9 | 113416736820265 |
10 | 26397601788839 |
11 | 8458184031296 |
12 | 2b6404751811b |
13 | 119638b1714b8 |
14 | 6739178d7db1 |
15 | 30b9dede620e |
hex | 18022bad73a7 |
26397601788839 has 2 divisors, whose sum is σ = 26397601788840. Its totient is φ = 26397601788838.
The previous prime is 26397601788823. The next prime is 26397601788841. The reversal of 26397601788839 is 93888710679362.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26397601788839 - 24 = 26397601788823 is a prime.
Together with 26397601788841, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 26397601788839.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26397601788869) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13198800894419 + 13198800894420.
It is an arithmetic number, because the mean of its divisors is an integer number (13198800894420).
Almost surely, 226397601788839 is an apocalyptic number.
26397601788839 is a deficient number, since it is larger than the sum of its proper divisors (1).
26397601788839 is an equidigital number, since it uses as much as digits as its factorization.
26397601788839 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1316818944, while the sum is 77.
The spelling of 26397601788839 in words is "twenty-six trillion, three hundred ninety-seven billion, six hundred one million, seven hundred eighty-eight thousand, eight hundred thirty-nine".
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