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264440611065383 is a prime number
BaseRepresentation
bin111100001000000111100000…
…101011111100111000100111
31021200022021102212011112002022
4330020013200223330320213
5234130043332413043013
62334230201210133355
7106462126600605044
oct7410074053747047
91250267385145068
10264440611065383
11772936a6aa2975
12257aa44172125b
13b472847ac7a1c
144942dcb2541cb
152088a91984008
hexf081e0afce27

264440611065383 has 2 divisors, whose sum is σ = 264440611065384. Its totient is φ = 264440611065382.

The previous prime is 264440611065353. The next prime is 264440611065409. The reversal of 264440611065383 is 383560116044462.

264440611065383 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 264440611065383 - 210 = 264440611064359 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (264440611065343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132220305532691 + 132220305532692.

It is an arithmetic number, because the mean of its divisors is an integer number (132220305532692).

Almost surely, 2264440611065383 is an apocalyptic number.

264440611065383 is a deficient number, since it is larger than the sum of its proper divisors (1).

264440611065383 is an equidigital number, since it uses as much as digits as its factorization.

264440611065383 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9953280, while the sum is 53.

The spelling of 264440611065383 in words is "two hundred sixty-four trillion, four hundred forty billion, six hundred eleven million, sixty-five thousand, three hundred eighty-three".