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26544311344457 is a prime number
BaseRepresentation
bin1100000100100010101000…
…01111111001110101001001
310110222121111200211022001022
412002101110033321311021
511434400222201010312
6132242142134202225
75406522531435554
oct602212417716511
9113877450738038
1026544311344457
118504419821915
122b885701b3375
1311a716bb05b3a
1467aa7427969b
15310729bae172
hex1824543f9d49

26544311344457 has 2 divisors, whose sum is σ = 26544311344458. Its totient is φ = 26544311344456.

The previous prime is 26544311344427. The next prime is 26544311344567. The reversal of 26544311344457 is 75444311344562.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25835374288201 + 708937056256 = 5082851^2 + 841984^2 .

It is a cyclic number.

It is not a de Polignac number, because 26544311344457 - 26 = 26544311344393 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 26544311344399 and 26544311344408.

It is not a weakly prime, because it can be changed into another prime (26544311344417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13272155672228 + 13272155672229.

It is an arithmetic number, because the mean of its divisors is an integer number (13272155672229).

Almost surely, 226544311344457 is an apocalyptic number.

It is an amenable number.

26544311344457 is a deficient number, since it is larger than the sum of its proper divisors (1).

26544311344457 is an equidigital number, since it uses as much as digits as its factorization.

26544311344457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19353600, while the sum is 53.

The spelling of 26544311344457 in words is "twenty-six trillion, five hundred forty-four billion, three hundred eleven million, three hundred forty-four thousand, four hundred fifty-seven".