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2660107536551 is a prime number
BaseRepresentation
bin100110101101011010110…
…000111100100010100111
3100102022012110122010121202
4212231122300330202213
5322040400012132201
65354011520233115
7363120641662313
oct46553260744247
910368173563552
102660107536551
119361663a0223
1236b66876b79b
13163b02000a4a
1492a6d9bab43
15492dec40c6b
hex26b5ac3c8a7

2660107536551 has 2 divisors, whose sum is σ = 2660107536552. Its totient is φ = 2660107536550.

The previous prime is 2660107536547. The next prime is 2660107536607. The reversal of 2660107536551 is 1556357010662.

2660107536551 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2660107536551 - 22 = 2660107536547 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2660107536496 and 2660107536505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2660107536451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1330053768275 + 1330053768276.

It is an arithmetic number, because the mean of its divisors is an integer number (1330053768276).

Almost surely, 22660107536551 is an apocalyptic number.

2660107536551 is a deficient number, since it is larger than the sum of its proper divisors (1).

2660107536551 is an equidigital number, since it uses as much as digits as its factorization.

2660107536551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134000, while the sum is 47.

The spelling of 2660107536551 in words is "two trillion, six hundred sixty billion, one hundred seven million, five hundred thirty-six thousand, five hundred fifty-one".