Base | Representation |
---|---|
bin | 100110101101011010110… |
… | …000111100100010100111 |
3 | 100102022012110122010121202 |
4 | 212231122300330202213 |
5 | 322040400012132201 |
6 | 5354011520233115 |
7 | 363120641662313 |
oct | 46553260744247 |
9 | 10368173563552 |
10 | 2660107536551 |
11 | 9361663a0223 |
12 | 36b66876b79b |
13 | 163b02000a4a |
14 | 92a6d9bab43 |
15 | 492dec40c6b |
hex | 26b5ac3c8a7 |
2660107536551 has 2 divisors, whose sum is σ = 2660107536552. Its totient is φ = 2660107536550.
The previous prime is 2660107536547. The next prime is 2660107536607. The reversal of 2660107536551 is 1556357010662.
2660107536551 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2660107536551 - 22 = 2660107536547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2660107536496 and 2660107536505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2660107536451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1330053768275 + 1330053768276.
It is an arithmetic number, because the mean of its divisors is an integer number (1330053768276).
Almost surely, 22660107536551 is an apocalyptic number.
2660107536551 is a deficient number, since it is larger than the sum of its proper divisors (1).
2660107536551 is an equidigital number, since it uses as much as digits as its factorization.
2660107536551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134000, while the sum is 47.
The spelling of 2660107536551 in words is "two trillion, six hundred sixty billion, one hundred seven million, five hundred thirty-six thousand, five hundred fifty-one".
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