Base | Representation |
---|---|
bin | 100111000000101001000… |
… | …111011100100101011101 |
3 | 100111021111000221222121101 |
4 | 213000221013130211131 |
5 | 322410133322120103 |
6 | 5411304055233101 |
7 | 364451320010266 |
oct | 47005107344535 |
9 | 10437430858541 |
10 | 2680749410653 |
11 | 943999178806 |
12 | 373669678791 |
13 | 165a41675b32 |
14 | 93a6b22996d |
15 | 49aebeeba1d |
hex | 270291dc95d |
2680749410653 has 2 divisors, whose sum is σ = 2680749410654. Its totient is φ = 2680749410652.
The previous prime is 2680749410639. The next prime is 2680749410699. The reversal of 2680749410653 is 3560149470862.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1929204325764 + 751545084889 = 1388958^2 + 866917^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2680749410653 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2680749410594 and 2680749410603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2680749419653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1340374705326 + 1340374705327.
It is an arithmetic number, because the mean of its divisors is an integer number (1340374705327).
It is a 1-persistent number, because it is pandigital, but 2⋅2680749410653 = 5361498821306 is not.
Almost surely, 22680749410653 is an apocalyptic number.
It is an amenable number.
2680749410653 is a deficient number, since it is larger than the sum of its proper divisors (1).
2680749410653 is an equidigital number, since it uses as much as digits as its factorization.
2680749410653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 2680749410653 in words is "two trillion, six hundred eighty billion, seven hundred forty-nine million, four hundred ten thousand, six hundred fifty-three".
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