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2680749419653 is a prime number
BaseRepresentation
bin100111000000101001000…
…111011110110010000101
3100111021111000222102221201
4213000221013132302011
5322410133322412103
65411304055342501
7364451320045444
oct47005107366205
910437430872851
102680749419653
11943999184548
12373669681a31
13165a41679c66
1493a6b22cd5b
1549aebeee51d
hex270291dec85

2680749419653 has 2 divisors, whose sum is σ = 2680749419654. Its totient is φ = 2680749419652.

The previous prime is 2680749419651. The next prime is 2680749419659. The reversal of 2680749419653 is 3569149470862.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2612548530244 + 68200889409 = 1616338^2 + 261153^2 .

It is a cyclic number.

It is not a de Polignac number, because 2680749419653 - 21 = 2680749419651 is a prime.

Together with 2680749419651, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2680749419651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1340374709826 + 1340374709827.

It is an arithmetic number, because the mean of its divisors is an integer number (1340374709827).

It is a 1-persistent number, because it is pandigital, but 2⋅2680749419653 = 5361498839306 is not.

Almost surely, 22680749419653 is an apocalyptic number.

It is an amenable number.

2680749419653 is a deficient number, since it is larger than the sum of its proper divisors (1).

2680749419653 is an equidigital number, since it uses as much as digits as its factorization.

2680749419653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78382080, while the sum is 64.

The spelling of 2680749419653 in words is "two trillion, six hundred eighty billion, seven hundred forty-nine million, four hundred nineteen thousand, six hundred fifty-three".