Base | Representation |
---|---|
bin | 100111001100011101001… |
… | …111000101110000111111 |
3 | 100112111020010010011111211 |
4 | 213030131033011300333 |
5 | 323112123324132011 |
6 | 5421202535225251 |
7 | 365410554443461 |
oct | 47143517056077 |
9 | 10474203104454 |
10 | 2693434989631 |
11 | 949308919a81 |
12 | 376009b18227 |
13 | 166cb386aa99 |
14 | 94511d0a131 |
15 | 4a0e0a41b21 |
hex | 2731d3c5c3f |
2693434989631 has 2 divisors, whose sum is σ = 2693434989632. Its totient is φ = 2693434989630.
The previous prime is 2693434989629. The next prime is 2693434989703. The reversal of 2693434989631 is 1369894343962.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2693434989631 - 21 = 2693434989629 is a prime.
It is a super-2 number, since 2×26934349896312 (a number of 26 digits) contains 22 as substring.
Together with 2693434989629, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2693434989131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1346717494815 + 1346717494816.
It is an arithmetic number, because the mean of its divisors is an integer number (1346717494816).
Almost surely, 22693434989631 is an apocalyptic number.
2693434989631 is a deficient number, since it is larger than the sum of its proper divisors (1).
2693434989631 is an equidigital number, since it uses as much as digits as its factorization.
2693434989631 is an evil number, because the sum of its binary digits is even.
The product of its digits is 181398528, while the sum is 67.
The spelling of 2693434989631 in words is "two trillion, six hundred ninety-three billion, four hundred thirty-four million, nine hundred eighty-nine thousand, six hundred thirty-one".
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