Base | Representation |
---|---|
bin | 1100011011000001100001… |
… | …01000110101011001111101 |
3 | 10120201110110022121001122022 |
4 | 12031200300220311121331 |
5 | 12040024310322412222 |
6 | 134033100210525525 |
7 | 5516400652665215 |
oct | 615406050653175 |
9 | 116643408531568 |
10 | 27316808013437 |
11 | 8781aa1a80978 |
12 | 309221b8968a5 |
13 | 1231c6ba21637 |
14 | 6a61d79bb245 |
15 | 32588d646042 |
hex | 18d830a3567d |
27316808013437 has 2 divisors, whose sum is σ = 27316808013438. Its totient is φ = 27316808013436.
The previous prime is 27316808013419. The next prime is 27316808013527. The reversal of 27316808013437 is 73431080861372.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24866787928921 + 2450020084516 = 4986661^2 + 1565254^2 .
It is a cyclic number.
It is not a de Polignac number, because 27316808013437 - 238 = 27041930106493 is a prime.
It is a super-3 number, since 3×273168080134373 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (27316802013437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13658404006718 + 13658404006719.
It is an arithmetic number, because the mean of its divisors is an integer number (13658404006719).
Almost surely, 227316808013437 is an apocalyptic number.
It is an amenable number.
27316808013437 is a deficient number, since it is larger than the sum of its proper divisors (1).
27316808013437 is an equidigital number, since it uses as much as digits as its factorization.
27316808013437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4064256, while the sum is 53.
The spelling of 27316808013437 in words is "twenty-seven trillion, three hundred sixteen billion, eight hundred eight million, thirteen thousand, four hundred thirty-seven".
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