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27341366544251 is a prime number
BaseRepresentation
bin1100011011101111010000…
…11100001100011101111011
310120210210211211210200120122
412031313220130030131323
512040430104313404001
6134052241141243455
75521230360030344
oct615675034143573
9116723754720518
1027341366544251
118791454698631
123096b3440358b
131234383957086
146a74874870cb
153263296b2b1b
hex18dde870c77b

27341366544251 has 2 divisors, whose sum is σ = 27341366544252. Its totient is φ = 27341366544250.

The previous prime is 27341366544223. The next prime is 27341366544253. The reversal of 27341366544251 is 15244566314372.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-27341366544251 is a prime.

Together with 27341366544253, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 27341366544193 and 27341366544202.

It is not a weakly prime, because it can be changed into another prime (27341366544253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13670683272125 + 13670683272126.

It is an arithmetic number, because the mean of its divisors is an integer number (13670683272126).

Almost surely, 227341366544251 is an apocalyptic number.

27341366544251 is a deficient number, since it is larger than the sum of its proper divisors (1).

27341366544251 is an equidigital number, since it uses as much as digits as its factorization.

27341366544251 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14515200, while the sum is 53.

The spelling of 27341366544251 in words is "twenty-seven trillion, three hundred forty-one billion, three hundred sixty-six million, five hundred forty-four thousand, two hundred fifty-one".