Base | Representation |
---|---|
bin | 11010001010111001… |
… | …100000100000011111 |
3 | 2200112100100202110122 |
4 | 122022321200200133 |
5 | 430022113304233 |
6 | 20524203225155 |
7 | 2013230130446 |
oct | 321271404037 |
9 | 80470322418 |
10 | 28100134943 |
11 | 10a0a880321 |
12 | 55428181bb |
13 | 285a8aaaaa |
14 | 1507db7d5d |
15 | ae6e45d98 |
hex | 68ae6081f |
28100134943 has 2 divisors, whose sum is σ = 28100134944. Its totient is φ = 28100134942.
The previous prime is 28100134919. The next prime is 28100134967. The reversal of 28100134943 is 34943100182.
It is a balanced prime because it is at equal distance from previous prime (28100134919) and next prime (28100134967).
It is a cyclic number.
It is not a de Polignac number, because 28100134943 - 28 = 28100134687 is a prime.
It is a super-2 number, since 2×281001349432 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (28100134903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14050067471 + 14050067472.
It is an arithmetic number, because the mean of its divisors is an integer number (14050067472).
Almost surely, 228100134943 is an apocalyptic number.
28100134943 is a deficient number, since it is larger than the sum of its proper divisors (1).
28100134943 is an equidigital number, since it uses as much as digits as its factorization.
28100134943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 28100134943 in words is "twenty-eight billion, one hundred million, one hundred thirty-four thousand, nine hundred forty-three".
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