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285640849612799 is a prime number
BaseRepresentation
bin100000011110010011111000…
…1010111111101111111111111
31101110100222221221012121020222
41000330213301113331333333
5244414414430000102144
62451301332245531555
7114110604351145352
oct10074476127757777
91343328857177228
10285640849612799
1183017670a6821a
122805313a713bbb
13c34ca7cc29075
14507713b574299
1523052924262ee
hex103c9f15fdfff

285640849612799 has 2 divisors, whose sum is σ = 285640849612800. Its totient is φ = 285640849612798.

The previous prime is 285640849612793. The next prime is 285640849612801. The reversal of 285640849612799 is 997216948046582.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-285640849612799 is a prime.

It is a super-2 number, since 2×2856408496127992 (a number of 30 digits) contains 22 as substring.

Together with 285640849612801, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (285640849612793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 142820424806399 + 142820424806400.

It is an arithmetic number, because the mean of its divisors is an integer number (142820424806400).

Almost surely, 2285640849612799 is an apocalyptic number.

285640849612799 is a deficient number, since it is larger than the sum of its proper divisors (1).

285640849612799 is an equidigital number, since it uses as much as digits as its factorization.

285640849612799 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3762339840, while the sum is 80.

The spelling of 285640849612799 in words is "two hundred eighty-five trillion, six hundred forty billion, eight hundred forty-nine million, six hundred twelve thousand, seven hundred ninety-nine".